Any way i wont consume much bytes and will start
1. Faster Multiplication
Suppose you have to multiply two 2 digit no's . If both the numbers have same Ten's digit the ideal way is to choose the suitable base. (Base can you on one's choice)
e.g
MULTIPLY
82
*85
(As both the numbers have same Ten's digit i.e '8' , and now to choose the base , we can choose the base depending upon the convenience lets choose the base as 80
Hence 82 can be written as 80 + 2 and 85 can be written as 80 + 5
Now trick
Step 1
82 + 2 (why + 2 , because we have chosen base as 80 and the given number is 82(80+2) and 85 + 5 (why + 5, because we have chosen base as 80 and the given number is 85(80+5)
Step 2
Cross Addition i.e either Add 82 + 5 OR 85 + 2 in both case the result is 87 ------(i)
Step 3
Now Multiply (i) with the base chosen i.e 80 hence 87 * 80 = 6960-----------(ii)
Step 4
Multiply + 2 with + 5 i.e +10 ------------ (iii)
Step 5
Now add ii and iii
i.e 6960 + 10 = 6970 is the result
||ly lets do multiplication of 108 with 98
Choose the base lets choose 100 as the base
So with respect to 100 base, 108 can be written as 100 + 8 and 98 can be written as 100 - 2
there fore
108 +8 ( 100 + 8 ) 98 -2 (100 - 2 )
Step 1
108 +8 (why +8 , because we have chosen base as 100 and the given number is 108(100+8) and 98 -2 (why -2, because we have chosen base as 100 and the given number is 98(100-2)
Step 2
Cross Addition i.e either Add 108 + (-2) OR 98 + 8in both case the result is 106 ------(i)
Step 3
Now Multiply (i) with the base chosen i.e 100 hence 106 * 100 = 10600-----------(ii)
Step 4
Multiply +8 with -2 i.e -16 ------------ (iii)
Step 5
Now add ii and iii
i.e 10600 + (-16) = 10584 is the result
2 .Square of a Number Less then Hundred
For this you have to mug up the Squares of Number less than equal to 25.
- Square range 26 to 49 The Formula is 25 - (50 - N) .(50 -N)^2 (Remember . is not decimal, its concatenation operator, you can see the usage of it while solving the square of the numbers) Lets take 27 square so directly use the formula N = 27 therefore 25 - (50 - 27).(50-27)^2 = > 25 - 23 . (23)^2 => 02. 529 => now add the Hundredth digit(5) of 529 to 02 i.e 7.29 hence the square of the number is 729. ||ly you can use the above formula to get the square of any number between that range.
- Square range 51 to 74 .The Formula is 25 + (N - 50). (N - 50) ^2 ( Remember . is not decimal, its a concatenation operator, you can see the usage of it while solving the square of the numbers). Lets calculate 68 Square . Use the direct Formula N = 68. therefore 25 + (68 - 50).(68-50)^2=> 25 + 18 . (18)^2 => 43.324 => Now add the hundredth digit (3) of 324 to 43 hence 43 +3.24 => 4624 is the Answer
- Square range 76 to 99. The Formula is N - (100-N).(100-N)^2 =>Lets calculate the square of the 84 . Hence 84 - (100 - 84).(100-84) ^2 => 84 - 16 . 256 => 68.256 => Now add the hundredth digit (2) of 256 to 68 , hence the it becomes 68+2.56 => 7056 is the answer
- Lets take 124*124
124 + 24 . 24 *24 (Remember . is again not the decimal point, it's a concatenation operator) Now let me radiate few energy particles how I derived the above figure.
- In case of finding the square of number greater than 100 but less than 199, choose the original three digit no(124) add to its last two digit number (24)! 124 + 24 = 148 ---(i)
- Now square the last two digits of the numbers in this case its 24 * 24 = 576 -------(ii)
- Now club i and ii, in such a way that the hundredth digit of ii gets added to i hence 148+5.76 => 153.76
- Hence the answer is 15376 :)
- Lets take 156*156
156+56 = 212.3136 => add the Thousand and Hundredth digit( 31) to 212 i.e212 + 31 . 36=>243.36 hence the answer is 24336
4. Any Number multiplied by 9
- If any number is multiplied by 9, here is the trick
Add 0 to end of the multiplicand i.e 760 and now subtract the original multiplicand (76)from the number thats has been modified by adding the 0 at the end(760 ) hence 760 - 76 = 684 and 684 is the answer
Lets take another number e.g 15678 * 9
Add 0 to the end of the multiplicand hence the number becomes 156780 and now subtract the original multiplicand (15678) from the number that has been modified by adding 0 at the end(156780) hence 156780 - 15678 = 141102. Answer
Isn't it Great????
5. Any number multiplied by 99... series
1. Lets take 765 * 999 (In which both the numbers have same digits)
765-1. 999-764 (Remember . is not decimal its a concatenation operator)
Step 1
Let me expand how i derive the above one, Any number which we are going to multiply with 999 series. Subtract 1 from that number hence in that case the given number is 765 and hence the new number formed is 765-1 = 764 ------- i
Step 2
Now subtract ( i) from 99 series number , (99 series is nothing but 9, 99, 999, 9999 ...) in this case the number given is 999 . Therefore 999- 764 = 235 ------- ii
Step 3
Concatenate i and ii hence the answer is 764235
||ly you can take try numerous examples.
2. Lets take 8723 * 999 ( In which the Number of digits of 99 series number is less than the multiplicand)
Step 1.
Same as above one hence 8723 - 1 = 8722--------i
Step 2
Now subtract ( i) from 99 series number , (99 series is nothing but 9, 99, 999, 9999 ...) in this case the number given is 999 . Therefore 999- 8722= (-8)277(why -8 because the 99 series is three digit number ------- ii
Step 3
Concatenate i and ii if any carry forward is there then add to the i , in this case the carry forward is -8 hence 8722+(-8).277 = 8714277 is the answer
3. Lets take 759 * 9999 ( In which the number of 99 series digit is greater than the multiplicand)
Step 1:
Same as above one i.e 759 - 1 = 758 ------ i
Step 2:
Now subtract ( i) from 99 series number , (99 series is nothing but 9, 99, 999, 9999 ...) in this case the number given is 9999 . Therefore 9999- 0758= 9241( In this case the last three digits will form the last three digits of the multiplication answer) ------- ii
Step 3:
Concatenate i and ii, in this case 9 is the carry forward, so rather than adding it to i , it will be concatenated to i i.e 7589.241. hence the answer is 7589241
Will post the next series of faster mathematics soon.
From
Abhit
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